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test(chain): applying changesets one-by-one vs aggregate should be same

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志宇 2024-05-05 14:00:49 +08:00 committed by Daniela Brozzoni
parent 6a3fb849e8
commit ed117de7a5
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1 changed files with 48 additions and 0 deletions
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48
crates/chain/tests/test_keychain_txout_index.rs
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@ -694,3 +694,51 @@ fn insert_descriptor_no_change() {
"inserting the same descriptor for keychain should return an empty changeset",
);
}
#[test]
fn applying_changesets_one_by_one_vs_aggregate_must_have_same_result() {
let desc = parse_descriptor(DESCRIPTORS[0]);
let changesets: &[ChangeSet<TestKeychain>] = &[
ChangeSet {
keychains_added: [(TestKeychain::Internal, desc.clone())].into(),
last_revealed: [].into(),
},
ChangeSet {
keychains_added: [(TestKeychain::External, desc.clone())].into(),
last_revealed: [(desc.descriptor_id(), 12)].into(),
},
];
let mut indexer_a = KeychainTxOutIndex::<TestKeychain>::new(0);
for changeset in changesets {
indexer_a.apply_changeset(changeset.clone());
}
let mut indexer_b = KeychainTxOutIndex::<TestKeychain>::new(0);
let aggregate_changesets = changesets
.iter()
.cloned()
.reduce(|mut agg, cs| {
agg.append(cs);
agg
})
.expect("must aggregate changesets");
indexer_b.apply_changeset(aggregate_changesets);
assert_eq!(
indexer_a.keychains().collect::<Vec<_>>(),
indexer_b.keychains().collect::<Vec<_>>()
);
assert_eq!(
indexer_a.spk_at_index(TestKeychain::External, 0),
indexer_b.spk_at_index(TestKeychain::External, 0)
);
assert_eq!(
indexer_a.spk_at_index(TestKeychain::Internal, 0),
indexer_b.spk_at_index(TestKeychain::Internal, 0)
);
assert_eq!(
indexer_a.last_revealed_indices(),
indexer_b.last_revealed_indices()
);
}